Daniil Medvedev beats Alexander Zverev, Alejandro Davidovich Fokina defeats Cristian Garin in Indian Wells last-16.

Daniil Medvedev beat Alexander Zverev in a challenging 6-7(5-7) 7-6(7-5) 7-5 last 16 tie at Indian Wells.

Zverev, meanwhile, had beaten Finland’s Emil Ruusuvuori in a 7-5 1-6 7-5 win, meaning both players had gone the distance in their previous match, with little time to recover.

Zverev reached the second round of the Australian Open in the first big tournament of the year, and Medevdev went just one further so both were looking to find their best form.

The first set was tough for them both, decided by an exacting 7-5 tie-break in Zverev’s favour.

Medvedev then won two consecutive sets by slim margins to reach the quarter-finals.

In another of the day’s men’s matches, Spain’s Alejandro Davidovich Fokina secured a 6-3 6-4 victory against Chile’s Cristian Garin.

The victor sent down five aces against his rival and also dominated when he forced break points, winning four of five offered up to him.

Cameron Norrie takes on Andrey Rublev for the chance to join Davidovich Fokina and Medvedev in the last eight.

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